How do you solve $32 - 2 (11 - 8) 2 = 36 x$ $32 - 2(11 - 8)2 = 36x$ ?

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Answer 1 · 2018-03-14T02:32:22

Use the Order of Operations to simplify!

Start by thinking about the Order of Operations:

Parenthesis
Exponents
Multiplication & Division
Addition & Subtraction

This will allow us to simplify before we start the algebra

$32 - 2 (11 - 8) \cdot 2 = 36 x$ $32-2(11-8)*2=36x$

Start with parenthesis

$32 - 2 (3) \cdot 2 = 36 x$ $32-2(3)*2=36x$

We have no exponents

Move to Multiplication & Division in the order they appear

$32 - 6 \cdot 2 = 36 x$ $32-6*2=36x$

$32 - 12 = 36 x$ $32-12=36x$

Now let's do the Addition & Subtraction in the order they appear

$20 = 36 x$ $20=36x$

The equation looks much simpler now!

To solve for $x$ $x$ , divide both sides by $36$ $36$ to isolate $x$ $x$

$20/36=cancel36x/cancel36$

$5/9=x$

How do you solve 32 - 2(11 - 8)2 = 36x32−2(11−8)2=36x32 - 2(11 - 8)2 = 36x?