How do you solve $3x + 11= 19- x$ ?

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Answer 1 · 2018-04-23T19:31:15

$x=2$

Get the $x's$ to one side:

$3x+11+x=19-cancelx+cancelx$

Collect like terms:

$4x+11=19$

Get $x$ on its own:

$4x+cancel11-cancel11=19-11$

$-> 4x=8$

Divide to solve for $x$

$x=8/4 -> 2$

$x=2$

Always put in this value to check:

$(3 xx 2)+11=19-2$

$6+11=17$

$17=17$ which is correct.

How do you solve 3x + 11= 19- x3x + 11= 19- x?