Question

How do you solve `3x-3=6x+1`?

Answer 1

`x=-4/3`

Explanation:

If we collect the terms in x on the left side of the equation and numeric values on the right side.

subtract 6x from both sides.

`3x-6x-3=cancel(6x)cancel(-6x)+1`

`rArr-3x-3=1`

add 3 to both sides.

`-3xcancel(-3)cancel(+3)=1+3`

`rArr-3x=4`

To solve for x, divide both sides by - 3

`(cancel(-3) x)/cancel(-3)=4/(-3)`

`rArrx=-4/3" is the solution"`