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How do you solve $\frac{3 x}{4} + 2 = 4 x - 1$ $(3x) /4 + 2 = 4x - 1$ ?

1 Answer

Aug 31, 2017

$\frac{3 x}{4} + 2 = 4 x - 1$ $(3x)/4+2=4x-1$

$4 x - \frac{3 x}{4} = 2 + 1$ $4x-(3x)/4=2+1$

$\frac{13 x}{4} = 3$ $(13x)/4=3$

$x = \frac{12}{13}$ $x=12/13$

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