How do you solve $3x-4=2x+8-5x$ ?

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Answer 1 · 2018-08-01T02:37:36

$x=2$

We can combine our right side like terms to get

$3x-4=-3x+8$

Next, let's get our variables on the left by adding $3x$ to both sides. We now have

$6x-4=8$

Next, to get our constants on the right, we can add $4$ to both sides to get

$6x=12$

Lastly, we can divide both sides by $6$ to get

$x=2$

Hope this helps!

How do you solve 3x-4=2x+8-5x3x-4=2x+8-5x?