How do you solve $3x - 5= 11x - 93$ ?

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Answer 1 · 2017-06-02T05:01:02

$x =11$

$3x - 5 = 11x - 93$

$3x -11x - 5 = - 93$

$3x -11x = - 93 + 5$

$-8x = - 88$

$cancel(-)8x = cancel(-) 88$

$8x =88$

$x =88 ÷ 8$

$color(blue)(x =11$

Now we can substitute $x$ for $11$ to prove our answer.

$3x - 5 = 11x - 93$

$3 xx 11 - 5 = 11 xx 11 - 93$

$33 - 5 = 121 - 93$

$28 = 121 - 93$

$121 - 93 = 28$

$28 = 28$

How do you solve 3x - 5= 11x - 933x - 5= 11x - 93?