How do you solve $3x-5=7x+3$ ?

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Answer 1 · 2018-04-05T16:21:54

$x = -2$
Here's how I did it:

$3x-5 = 7x + 3$

First, let's subtract $7x$ on both sides of the equation:
$-4x - 5 = 3$

Now, let's add $5$ to both sides of the equation:
$-4x = 8$

Finally, let's divide both sides by $-4$ to get the value of $x$ :
$x = -2$

How do you solve 3x-5=7x+33x-5=7x+3?