How do you solve #4( 3x + 20) + 10= 50#?

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Answer 1 · 2018-05-22T22:09:35

#-3.bar(3)# or #-3 1/3#.

First, you use the distributive property.

#4 times 3x = 12x#

#4 times 20 = 80#

So now you have:

#12x + 80 + 10 = 50#

Now you can combine like terms:

#80 + 10 = 90#

Now you have:

#12x + 90 = 50#

Subtract #90# from both sides to make it cancel out so you are left with:

#12x = -40#

You have to get #x# by itself, so you divide by #12# on both sides and that cancels out the #12#.

#(12x)/12 = -40/12#

#x = -3.33" "# (rounded answer)

#x = -3.bar(3) = -3 1/3#

Answer 2 · 2018-05-22T22:54:27

#x=-10/3#

Let's start by distributing the #4# to both of the terms in parenthesis. Doing this, we get

#12x+80+10=50#

We can combine like terms on the left to get

#12x+90=50#

Next, we can subtract #90# from both sides to get

#12x=-40#

We can divide both sides by #12# to get

#x=-40/12#

To simplify this fraction, we can divide the top and bottom by #4#. Doing this, we get

#x=-10/3#

Hope this helps!