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How do you solve $\frac{4}{3} x + \frac{4}{3} = 4 x + \frac{3}{2}$ $4/3x + 4/3= 4x+3/2$ ?

1 Answer

Mar 7, 2018

$x = - \frac{1}{16}$ $x=-1/16$

Explanation:

Given
$XXX \frac{4}{3} x + \frac{4}{3} = 4 x + \frac{3}{2}$ $color(white)("XXX")4/3x+4/3=4x+3/2$

If we multiply everything (on both sides) by $6$ $6$ we can get rid of the fractions and make this a simpler equation:
$XXX 8 x + 8 = 24 x + 9$ $color(white)("XXX")8x+8=24x+9$

Re-arranging by subtraction $(24 x + 8)$ $(24x+8)$ from both sides:
$XXX - 16 x = 1$ $color(white)("XXX")-16x=1$

Then divide both sides by $(- 16)$ $(-16)$
$XXX x = - \frac{1}{16}$ $color(white)("XXX")x=-1/16$

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