How do you solve $4 + 3 x = 6 x - 17$ $4+3x=6x-17$ ?

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Answer 1 · 2018-05-25T01:03:45

$x = 7$ $x = 7$

What you do to one side, you do to the other. Add $17$ $17$ to both sides:

$4 + 3 x + 17 = 6 x - 17 + 17$ $4 + 3x + 17 = 6x - 17 + 17$

This turns into

$3 x + 21 = 6 x$ $3x + 21 = 6x$

Minus $3 x$ $3x$ from both sides:

$3 x - 3 x + 21 = 6 x - 3 x$ $3x - 3x + 21 = 6x - 3x$

Which makes;

$21 = 3 x$ $21 = 3x$

Divide $3$ $3$ from both sides:

$\frac{21}{3} = \frac{3 x}{3}$ $21/3 = (3x)/3$

This makes;

$7 = x$ $7 = x$

That's your answer.

How do you solve 4+3x=6x-174+3x=6x−174+3x=6x-17?