How do you solve $4(-8x+5)=-32x-26$ ?

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Answer 1 · 2017-02-20T14:35:47

See the entire solution process below:

First, expand the terms within parenthesis on the left side of the equation:

$(4 xx -8x) + (4 xx 5) = -32x - 26$

$-32x + 20 = -32x - 26$

Now, add $color(red)(32x)$ to each side of the equation:

$color(red)(32x) - 32x + 20 = color(red)(32x) - 32x - 26$

$0 + 20 = 0 - 26$

$20 != -26$

Therefore there is no solution to this problem other than the null or empty set or $x = {O/}$

How do you solve 4(-8x+5)=-32x-264(-8x+5)=-32x-26?