How do you solve $4( a - 1) = 7a + 2$ ?

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Answer 1 · 2018-04-21T10:31:47

$a=-2$

To get to those follow these steps:

Expand the brackets, so $4(a-1)$ becomes $4a-4$
Rearrange so you have the variables on the same side $-> -4 -2 = 7a-4a$ (change signs when moving across the equals sign)
Simplify $-> -6 = 3a$
Divide both sides by $3$ so $a$ is by itself $-> -6/3=a$
$-6/3 = -2$ , therefore, $a$ must equal $-2$

Answer 2 · 2018-04-21T10:34:03

a = -2

$4(a-1) = 7a + 2$

On the left hand side, multiply each term inside the brackets by 4

$4a - 4 = 7a + 2$

Subtract 2 from both sides

$4a - 6 = 7a$

Subtract 4a from both sides

$-6 = 7a - 4a$
$-6 = 3a$

Divide both sides by 3

$-2 = a$
$a = -2$

How do you solve 4( a - 1) = 7a + 24( a - 1) = 7a + 2?