First, expand the terms in parenthesis on each side of the equation:
(4 xx x) + (4 xx 0.5) = (2 xx x) - (2 1.5)(4×x)+(4×0.5)=(2×x)−(21.5)
4x + 2 = 2x - 34x+2=2x−3
Next, subtract color(red)(2)2 and color(blue)(2x)2x from each side of the equation to isolate the xx term while keeping the equation balanced:
4x + 2 - color(red)(2) - color(blue)(2x) = 2x - 3 - color(red)(2) - color(blue)(2x)4x+2−2−2x=2x−3−2−2x
4x - color(blue)(2x) + 2 - color(red)(2) = 2x - color(blue)(2x) - 3 - color(red)(2)4x−2x+2−2=2x−2x−3−2
2x + 0 = 0 - 52x+0=0−5
2x = -52x=−5
Now, divide each side of the equation by color(red)(2)2 to solve for xx while keeping the equation balanced:
(2x)/color(red)(2) = -5/color(red)(2)2x2=−52
(color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2)) = -2.5
x -2.5