How do you solve $4 d + 7 = - (2 d + 41)$ $4d + 7 = - (2d + 41)$ ?

Question

1552 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-12-01T21:47:21

$d = - 8$ $d=-8$

Distribute the negative sign on the right side.

$4 d + 7 = - 2 d - 41$ $4d+7=-2d-41$

Subtract $7$ $7$ from both sides.

$4 d + 7 - 7 = - 2 d - 41 - 7$ $4d+7-7=-2d-41-7$

$4 d = - 2 d - 48$ $4d=-2d-48$

Add $2 d$ $2d$ to both sides.

$4 d + 2 d = - 2 d + 2 d - 48$ $4d+2d=-2d+2d-48$

$6 d = - 48$ $6d=-48$

Divide both sides by $6$ $6$ .

$\frac{6 d}{6} = \frac{- 48}{6}$ $(6d)/6=(-48)/6$

$d = - 8$ $d=-8$

How do you solve 4d+7=−(2d+41)4d + 7 = - (2d + 41)?