How do you solve $4 x - 15 = 6 x - 1$ $4x-15=6x-1$ ?

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Answer 1 · 2017-11-15T03:56:16

$x = - 7$ $x = - 7$

So, my assumption is that you’re solving for $x$ $x$ , and so you’d add the one to the negative fifteen, leaving you with

$4 x - 14 = 6 x$ $4x - 14 = 6x$

Then you’d subtract the $4 x$ $4x$ from the $6 x$ $6x$ , leaving you with

$- 14 = 2 x$ $-14 = 2x$

You’d divide two from both sides, giving you

$x = - 7$ $x = -7$

Hope this helps!

How do you solve 4x−15=6x−14x-15=6x-1?