How do you solve $4 x + 2 = 12 x + 3$ $4x + 2= 12x + 3$ ?

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Answer 1 · 2018-03-25T09:55:09

$x = - \frac{1}{8}$ $x=-1/8$

We have:

$4 x + 2 = 12 x + 3$ $4x+2=12x+3$

$8 x + 3 = 2$ $8x+3=2$

$8 x = - 1$ $8x=-1$

$x = - \frac{1}{8}$ $x=-1/8$

Answer 2 · 2018-03-25T10:00:58

$x = - \frac{1}{8}$ $x=-1/8$

Solving an equation means finding all the possible values of the variable to satisfy the provided conditions.

The given equation is

$4 x + 2 = 12 x + 3$ $4x+2=12x+3$

Now let's begin with eliminating $3$ $3$ from the RHS by subtracting $3$ $3$ from both sides.

$4 x + 2 - 3 = 12 x + 3 - 3$ $4x+2-3=12x+3-3$

$4 x - 1 = 12 x$ $4x-1=12x$

Next, let's bring the variable terms together by subtracting $4 x$ $4x$ from both sides

$4 x - 1 - 4 x = 12 x - 4 x$ $4x-1-4x=12x-4x$

$- 1 = 8 x$ $-1=8x$

By dividing by $8$ $8$ on both sides of the equation, we get

$\frac{- 1}{8} = \frac{8 x}{8}$ $(-1)/8 = (8x)/8$

$- \frac{1}{8} = x$ $-1/8=x$

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