How do you solve $-4x - 2= - 2+ 8x$ ?

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Answer 1 · 2018-01-26T03:55:49

$x=0$

Isolate $x$ on to one side.

$-4x-2=-2+8x$

I can add $4x$ to both sides to eliminate $-4x$ on the $LHS$ .

$:.cancel(-4x)-2+cancel(4x)=-2+8x+4x$

$-2=12x-2$

Adding $2$ to both sides eliminates both $2$ 's.

$cancel(-2)+cancel(2)=12x-cancel(2)+cancel(2)$

$12x=0$

$x=0$

How do you solve -4x - 2= - 2+ 8x-4x - 2= - 2+ 8x?