How do you solve $4x + 7 = 6x - 1$ ?

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Answer 1 · 2018-05-07T03:21:30

$x=4$ .

Start by bringing all of the variables onto one side of the equation. In this case, Let's subtract 4x from both sides to give us:

$7=6x-4x-1$

Perform indicated steps as allowed (subtract $4x$ from $6x$ , giving us $2x$ ). So:

$7=2x-1$

Let's get all of the non-variables onto one side of the equation, the simplest way to do this is to add $1$ to both sides:

$7+1 =2x$

Perform indicated steps as allowed (add $7$ plus $1$ , giving us $8$ ). Now, we are looking at

$8=2x$

Let's divide both sides by the coefficient of $x$ (which is $2$ ), and that gives us:

$4=x$

Because the equals sign is transitive, we can also state this as

$x=4$

How do you solve 4x + 7 = 6x - 14x + 7 = 6x - 1?