How do you solve $4 x \times 8 = 2 (8 x + 4) + 8 \times 4$ $4x\times 8=2(8x+4)+8\times 4$ ?

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Answer 1 · 2017-02-08T04:27:14

$x = \frac{5}{2}$ $x=5/2$ .

Solve $4 x \times 8 = 2 (8 x + 4) + 8 \times 4)$ $4x xx8=2(8x+4)+8xx4)$

Multiply from left to right.

$32 x = 16 x + 8 + 32$ $32x=16x+8+32$

Simplify.

$32 x = 16 x + 40$ $32x=16x+40$

Subtract $16 x$ $16x$ from both sides.

$32 x - 16 x = 40$ $32x-16x=40$

Simplify.

$16 x = 40$ $16x=40$

Divide both sides by $16$ $16$ .

$x = \frac{40}{16}$ $x=40/16$

Simplify.

$x = \frac{5}{2}$ $x=5/2$

How do you solve 4x\times 8=2(8x+4)+8\times 44x×8=2(8x+4)+8×44x\times 8=2(8x+4)+8\times 4?