How do you solve $5 M + 24 = 51 + 2 M$ $5M + 24 = 51 + 2M$ ?

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Answer 1 · 2016-12-05T15:40:03

$M = 9$ $M = 9$

First, isolate the $M$ $M$ terms on one side of the equation and the constants on the other while keeping the equation balanced:

$5 M + 24 - 24 - 2 M = 51 + 2 M - 24 - 2 M$ $5M + 24 - 24 - 2M = 51 + 2M - 24 - 2M$

$5 M - 2 M + 24 - 24 = 51 - 24 + 2 M - 2 M$ $5M - 2M + 24 - 24 = 51 - 24 + 2M - 2M$

$5 M - 2 M + 0 = 51 - 24 + 0$ $5M - 2M + 0 = 51 - 24 + 0$

$5 M - 2 M = 51 - 24$ $5M - 2M = 51 - 24$

Now consolidate like terms:

$(5 - 2) M = 27$ $(5 - 2)M = 27$

$3 M = 27$ $3M = 27$

Finally, solve for $M$ $M$ while keeping the equation balanced:
$\frac{3 M}{3} = \frac{27}{3}$ $(3M)/3 = 27/3$

$(cancel(3)M)/cancel(3) = 27/3$

$M = 27/3$

$M = 9$

How do you solve 5M + 24 = 51 + 2M5M+24=51+2M5M + 24 = 51 + 2M?