How do you solve $5 x + 15 = 8 x - 40$ $5x+15=8x-40$ ?

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Answer 1 · 2016-12-30T04:35:04

$x = 18 \frac{1}{3}$ $x=18 1/3$

$5 x + 15 = 8 x - 40$ $5x+15=8x-40$

Add $40$ $40$ to each side.

$5 x + 55 = 8 x$ $5x+55=8x$

Subtract $5 x$ $5x$ from each side.

$55 = 3 x$ $55=3x$

Divide both sides by $3$ $3$ .

$\frac{55}{3} = \frac{3 x}{3}$ $55/3=(3x)/3$

$18 1/3=(cancel3x)/cancel3$

$18 1/3=x$ or $x=18 1/3$

How do you solve 5x+15=8x-405x+15=8x−405x+15=8x-40?