How do you solve $6 + 3 (1 + 3 a) = 2 a$ $6+3(1+3a)=2a$ ?

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Answer 1 · 2018-03-03T22:42:28

$a = - \frac{9}{7}$ $a=-9/7$

We can distribute the $3$ $3$ to both terms in the parenthesis to get:

$6 + 3 + 9 a = 2 a$ $6+color(blue)(3+9a)=2a$

NOTE: What I have in blue is the product of our distribution.

We can further simplify the left side of the equation to get:

$9 + 9 a = 2 a$ $9+9a=2a$

We can subtract $9 a$ $9a$ from both sides of the equation to get:

$9 = - 7 a$ $9=-7a$

We can divide both sides by $- 7$ $-7$ to get:

$a = - \frac{9}{7}$ $a=-9/7$

How do you solve 6+3(1+3a)=2a6+3(1+3a)=2a6+3(1+3a)=2a?