How do you solve $7-3x=x-4(2+x)$ ?

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Answer 1 · 2016-07-02T00:47:52

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To solve $7-3x=x-4(2+x)$

Begin by distributing the $4$

$7-3x=x-8-4x$

Combine like terms

$7-3x=-3x-8$

Combine the variables and constants on opposite sides of the equal sign

$7 + 8 cancel(-3x) cancel(+3)=-3x +3x cancel(-8) cancel(+8)$

$15=0x$

No Solution

How do you solve 7-3x=x-4(2+x)7-3x=x-4(2+x)?