How do you solve $7 x - 4 (2 - 3 x) = 3 x - 6 + 8 x$ $7x-4(2-3x) = 3x-6+8x$ ?

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Answer 1 · 2017-12-23T14:53:44

$x = 0.25$ $x = 0.25$

Try to shift all the expressions to one side

$7 x - 4 (2 - 3 x) - 3 x + 6 - 8 x = 0$ $7x-4(2-3x)-3x+6-8x=0$

Expand the brackets and add all like terms

$7 x - 8 + 12 x - 3 x + 6 - 8 x = 0$ $7x-8+12x-3x+6-8x=0$

$8 x - 2 = 0$ $8x-2=0$

Make x the subject

$x = \frac{2}{8}$ $x =2/8$

$x = 0.25$ $x = 0.25$

How do you solve 7x-4(2-3x) = 3x-6+8x7x−4(2−3x)=3x−6+8x7x-4(2-3x) = 3x-6+8x?