How do you solve 8- 6x = 5x + 41? Algebra Linear Equations Equations with Variables on Both Sides 1 Answer Serena D. May 30, 2018 x=-3 Explanation: Isolate x: 8-6x=5x+41 rarr Add 6x to each side 8=11x+41 rarr Subtract 41 from each side 11x=-33 rarr Divide 11 from each side x=-3 Answer link Related questions How do you check solutions to equations with variables on both sides? How do you solve 125+20w-20w=43+37w-20w? How do you solve for x in 3(x-1) = 2 (x+3)? Is there a way to solve for x without using distribution in 4(x-1) = 2 (x+3)? How do you solve for t in 2/7(t+2/3)=1/5(t-2/3)? How do you solve 5n + 34 = −2(1 − 7n)? How do you simplify first and then solve −(1 + 7x) − 6(−7 − x) = 36? Why is the solution to this equation -15y + 7y + 1 = 3 - 8y, "no solution"? How do you solve for variable w in the equation v=lwh? How do you solve y-y_1=m(x-x_1) for m? See all questions in Equations with Variables on Both Sides Impact of this question 2022 views around the world You can reuse this answer Creative Commons License