How do you solve $8p-2p+3=10p-6$ ?

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Answer 1 · 2016-08-06T07:26:07

$p=9/4$

To solve a linear equation like $16-2.4d=-8$ , we should all constant terms to one side and variable term to other side. Thus

$8p-2p+3=10p-6$ or

$8p-2pul(-10p-3)+3=10pul(-10p-3)-6$ or

$8p-2p-10p-cancel3+cancel3=cancel(10p)-cancel(10p)-3-6$ or

$8p-2p-10p=-3-6$ or

$(8-2-10)p=-9$ or

$-4p=-9$ i.e.

$p=(-9)/(-4)=9/4$

How do you solve 8p-2p+3=10p-68p-2p+3=10p-6?