How do you solve $8z=4(2z+1)$ ?

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Answer 1 · 2017-02-05T11:50:29

See the entire solution process below:

First, expand the terms within parenthesis on the right hand side of the equation:

$8z = (4 xx 2z) + (4 xx 1)$

$8z = 8z + 4$

Now, subtract $8z$ from each side of the equation:

$-8z + 8z = -8z + 8z + 4$

$0 = 0 + 4$

$0 = 4$

However, we know $0 != 4$ , therefore there is no solution to this equation, or $x$ equals the null set, or $x = {O/}$

How do you solve 8z=4(2z+1)8z=4(2z+1)?