How do you solve for x: $3 x + 3 = - 2 x - 12$ $3x+3=-2x-12$ ?

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Answer 1 · 2018-03-18T21:03:55

-3

(move all to one side)
$= 5 x + 15 = 0$ $= 5x + 15 = 0$
(divide by 5)
$= x + 3 = 0$ $= x + 3 = 0$
(subtract 3)
$x = - 3$ $x = -3$

Answer 2 · 2018-03-18T21:09:12

$x = - 3$ $x=-3$

We want to get $x$ $x$ by itself. To start, we can add $2 x$ $2x$ to both sides to get:

$5 x + 3 = - 12$ $5x+3=-12$

We can now subtract $3$ $3$ from both sides to get:

$5 x = - 15$ $5x=-15$

Dividing by $5$ $5$ , we get:

$x = - 3$ $x=-3$

How do you solve for x: 3x+3=−2x−123x+3=-2x-12?