How do you solve for x in $\frac{1}{2} (x - 3) + (\frac{3}{2} - x) = 5 x$ $1/2( x - 3 ) + (3/2 - x ) = 5x$ ?

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Answer 1 · 2016-07-25T12:37:10

$x = 0$ $x = 0$

Remove the brackets first.

$\frac{1}{2} x - \frac{3}{2} + \frac{3}{2} - x = 5 x x 2 to get rid of denominators$ $1/2x-3/2 +3/2 -x = 5x" x 2 to get rid of denominators"$

$cancelcolor(blue)(2)xx1/cancel2x-color(blue)(cancel2)xx3/cancel2 +color(blue)(cancel2)xx3/cancel2 -color(blue)2xx x = color(blue)(2)xx5x$

$x-3 +3-2x=10x$

$0 = x$

How do you solve for x in 1/2( x - 3 ) + (3/2 - x ) = 5x12(x−3)+(32−x)=5x1/2( x - 3 ) + (3/2 - x ) = 5x?