How do you solve for x in $2(8-x)=-6$ ?

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Answer 1 · 2016-07-18T16:17:20

$x = 11$

To solve for $x$ , we must first distribute the $2$ across the parenthesis.

$2(8-x) = -6$

$16 - 2x = -6$

Now isolate the variable by getting it by itself on one side. Subtract $16$ from both sides.

$cancel(16-16)-2x = -6-16$

$-2x = -22$

Get rid of the coefficient to identify $x$ .

$(cancel(-2)x)/(cancel(-2)) = -22/-2$

$x = 11$

How do you solve for x in 2(8-x)=-62(8-x)=-6?