How do you solve $m + 4 (2 m - 3) = - 3$ $m+4(2m-3)=-3$ ?

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Answer 1 · 2017-01-07T18:52:17

See full solution process below:

First, we will expand the terms in parenthesis:

$m + 4 (2 m - 3) = - 3$ $m + color(red)(4)(2m - 3) = -3$

$m + (4 \times 2 m) - (4 \times 3) = - 3$ $m + (color(red)(4) xx 2m) - (color(red)(4) xx 3) = -3$

$m + 8 m - 12 = - 3$ $m + 8m - 12 = -3$

We can now combine like terms:

$1 m + 8 m - 12 = - 3$ $1m + 8m - 12 = -3$

$(1 + 8) m - 12 = - 3$ $(1 + 8)m - 12 = -3$

$9 m - 12 = - 3$ $9m - 12 = -3$

Next we can isolate the $m$ $m$ term and keep the equation balanced by adding $12$ $color(red)(12)$ to each side of the equation:

$9 m - 12 + 12 = - 3 + 12$ $9m - 12 + color(red)(12) = -3 + color(red)(12)$

$9 m - 0 = 9$ $9m - 0 = 9$

$9 m = 9$ $9m = 9$

Now we can solve for $m$ $m$ while keeping the equation balanced by dividing each side of the equation by $9$ $color(red)(9)$ :

$\frac{9 m}{9} = \frac{9}{9}$ $(9m)/color(red)(9) = 9/color(red)(9)$

$(color(red)(cancel(color(black)(9)))m)/cancel(color(red)(9)) = 1$

$m = 1$

How do you solve m+4(2m-3)=-3m+4(2m−3)=−3m+4(2m-3)=-3?