How do you solve $n+2=-14-n$ ?

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Answer 1 · 2016-07-30T16:17:33

Isolate $n$ on one side of the equation.

To do this, let's subtract 2 from each side:

$n=-16-n$

Next, let's add $n$ to each side:

$2n=-16$

Finally, let's divide each side by 2 to get our answer:

$n=-8$

How do you solve n+2=-14-nn+2=-14-n?