Question

How do you solve `t(2t+3)+20=2t(t-3)`?

Answer 1

t = -2.2222..., or t = `-20/9`

Explanation:

In this equation, we would first distribute the t through the (2t + 3), and distribute the 2t through the (t - 3). After doing so, you get, `2t^2 + 3t + 20 = 2t^2 - 6t`. Next, we would combine like terms getting,
`9t + 20 = 0`, where the two `2t^2`'s cancel each other out. Next, move the 20 to the other side, `9t = -20`. Finally, divide both sides by 9 to separate the t. Your final answer should be either, t = -2.2222..., or
t = `-20/9`.