How do you solve $t - 3 (t + \frac{4}{3}) = 2 t + 3$ $t-3(t+4/3) = 2t+3$ ?

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How do you solve $t - 3 (t + \frac{4}{3}) = 2 t + 3$ $t-3(t+4/3) = 2t+3$ ?

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Answer 1 · 2018-04-12T00:41:18

$t = \frac{4}{7}$ $t=4/7$

Explanation:

$t - 3 t - 4 = 2 t + 3$ $t-3t-4=2t+3$
$t - 5 t = - 7$ $t-5t=-7$ (move all the $t$ $t$ to the left side and all the constants to the right side)
$- 4 t = - 7$ $-4t=-7$ (the negative signs cancel out themselves)
$t = \frac{4}{7}$ $t=4/7$

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How do you solve $t - 3 (t + \frac{4}{3}) = 2 t + 3$ $t-3(t+4/3) = 2t+3$ ?

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How do you solve $t - 3 (t + \frac{4}{3}) = 2 t + 3$ $t-3(t+4/3) = 2t+3$ ?