How do you solve the triangle given $triangleABC, a=10, b=12, mangleB=30$ ?

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Answer 1 · 2018-02-26T08:51:36

$color(blue)(hat A = 24.62, hat C = 125.38, c = 19.57$

$color(blue)(a = 10, b = 12, hatB = 30^@$

Applying law of sines,

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$hat A = sin ^-1 ((a * sin B)/b) = sin ^-1 ((10 * sin 30)/12) = 24.62^@$

$hat C = 180 - 30 - 24.62 = 125.38^@$

$c = (sin C * b)/ sin B = (sin 125.38 * 12) / sin 30 = 19.57$

How do you solve the triangle given triangleABC, a=10, b=12, mangleB=30triangleABC, a=10, b=12, mangleB=30?