How do you solve the triangle given $triangleABC, a=15, b=19, mangleC=60$ ?

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Answer 1 · 2017-11-01T16:21:12

$c~~17.34, A=48^@29', B=71^@31'$

Use the Law of Cosine

$c^2=a^2+b^2-2ab cos C$

$c=sqrt(15^2+19^2-2(15)(19)cos60^@$

$c~~17.34$

$sin A/15 =sin60^@/17.34935157$

$sin A =(15 sin60^@)/17.34935157$

$A=sin^-1((15 sin60^@)/17.34935157)=48^@29'$

$B=180^@-60^@-48^@29'=71^@31'$

How do you solve the triangle given triangleABC, a=15, b=19, mangleC=60triangleABC, a=15, b=19, mangleC=60?