How do you solve the triangle given $△ A B C, b = 25, m ∠ B = 45, m ∠ C = 60$ $triangleABC, b=25, mangleB=45, mangleC=60$ ?

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Answer 1 · 2018-02-26T09:28:13

$ˆ A = 75^{\circ}, a = 34.15, c = 30.61$ $color(green)(hat A = 75^@, a = 34.15, c = 30.61$

$b = 25, ˆ B = 45^{\circ}, ˆ C = 60^{\circ}$ $color(blue)(b = 25, hat B = 45^@, hat C = 60^@$

Third angle $ˆ A = 180 - 45 - 60 = 75^{\circ}$ $hat A = 180 - 45 - 60 = 75^@$

Applying law of sines,

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$a = \frac{b sin A}{sin B} = \frac{25 \cdot sin 75}{sin 45} = 34.15$ $a = (b sin A) / sin B = (25 * sin 75) / sin 45 = 34.15$

$c = \frac{b sin C}{sin B} = \frac{25 \cdot sin 60}{sin 45} = 30.61$ $c = (b sin C) / sin B = (25 * sin 60) / sin 45 = 30.61$

How do you solve the triangle given △ABC,b=25,m∠B=45,m∠C=60triangleABC, b=25, mangleB=45, mangleC=60?