How do you solve this integral?

Question

How do you solve this integral?

$\int {tan}^{2} x d x$ $inttan^2xdx$

1 Answer

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Answer 1 · 2017-01-16T17:42:10

$\int {tan}^{2} x d x = tan x - x + C$ $int tan^2x dx = tanx -x +C$

Explanation:

Use the identity:

${tan}^{2} x = {sec}^{2} x - 1$ $tan^2x = sec^2x -1$

and remember that:

$\frac{d}{d x} tan x = {sec}^{2} x$ $d/(dx) tanx = sec^2x$

so we have:

$\int {tan}^{2} x d x = \int ({sec}^{2} x - 1) d x = \int {sec}^{2} x d x - \int d x = tan x - x + C$ $int tan^2x dx = int (sec^2x -1) dx = int sec^2xdx - int dx = tanx -x +C$

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How do you solve this integral?

$\int {tan}^{2} x d x$ $inttan^2xdx$

1 Answer

Explanation:

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Impact of this question

Science

Math

Humanities

... and beyond

How do you solve this integral?

inttan^2xdx∫tan2xdxinttan^2xdx

1 Answer

Explanation:

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Impact of this question

$\int {tan}^{2} x d x$ $inttan^2xdx$