How do you solve x/3 - 5 =3(x-2)? Algebra Linear Equations Equations with Variables on Both Sides 1 Answer EZ as pi Jul 29, 2017 x = 3/8 Explanation: x/3 -5 = 3(x-2)" "larr(xx3 to cancel the denominator) 3xxx/3 -3xx5 = 3xx3(x-2) x -15 = 9x-18 18-15 = 9x-x 3 = 8x x= 3/8 Answer link Related questions How do you check solutions to equations with variables on both sides? How do you solve 125+20w-20w=43+37w-20w? How do you solve for x in 3(x-1) = 2 (x+3)? Is there a way to solve for x without using distribution in 4(x-1) = 2 (x+3)? How do you solve for t in 2/7(t+2/3)=1/5(t-2/3)? How do you solve 5n + 34 = −2(1 − 7n)? How do you simplify first and then solve −(1 + 7x) − 6(−7 − x) = 36? Why is the solution to this equation -15y + 7y + 1 = 3 - 8y, "no solution"? How do you solve for variable w in the equation v=lwh? How do you solve y-y_1=m(x-x_1) for m? See all questions in Equations with Variables on Both Sides Impact of this question 2610 views around the world You can reuse this answer Creative Commons License