How do you solve $x-4=8+3x$ ?

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Answer 1 · 2016-04-24T01:15:28

$x=-6$

To solve the given problem, you want to move all variables with $x$ to one side of the equation and all other terms without $x$ to the other.

In your case, move all terms with $x$ to the right side and the ones without to the left.

Starting with,

$x-4=8+3x$

Subtract $x$ from both sides,

$x$ $color(red)(-x)-4=8+3x$ $color(red)(-x)$

$-4=8+2x$

Subtract $8$ from both sides,

$-4$ $color(red)(-8)=8$ $color(red)(-8)+2x$

$-12=2x$

Divide both sides by $2$ ,

$color(red)(color(black)(-12)/2)=color(red)(color(black)(2x)/2)$

$color(green)(|bar(ul(color(white)(a/a)x=-6color(white)(a/a)|)))$

How do you solve x-4=8+3xx-4=8+3x?