How many solutions does this equation $- 3 j = - 3 j - 2$ $-3j=-3j-2$ have?

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Answer 1 · 2016-12-09T23:59:32

There are no solutions.

If you add $3 j$ $3j$ to both sides of the equation, you get:

$cancel(3j)-cancel(3j)=cancel(3j)-cancel(3j)-2->$

$0=-2$

which is obviously FALSE.

How many solutions does this equation -3j=-3j-2−3j=−3j−2-3j=-3j-2 have?