Integration of sin-3xdx ? Calculus Introduction to Integration Integrals of Trigonometric Functions 1 Answer James ยท Stefan V. May 14, 2018 cos(-3x)/3+c Explanation: show below intsin(-3x)*dx=-1/3int-3*sin(-3x)*dx=-1/3[-cos(-3x)]=cos(-3x)/3+c Answer link Related questions How do I evaluate the indefinite integral intsin^3(x)*cos^2(x)dx ? How do I evaluate the indefinite integral intsin^6(x)*cos^3(x)dx ? How do I evaluate the indefinite integral intcos^5(x)dx ? How do I evaluate the indefinite integral intsin^2(2t)dt ? How do I evaluate the indefinite integral int(1+cos(x))^2dx ? How do I evaluate the indefinite integral intsec^2(x)*tan(x)dx ? How do I evaluate the indefinite integral intcot^5(x)*sin^4(x)dx ? How do I evaluate the indefinite integral inttan^2(x)dx ? How do I evaluate the indefinite integral int(tan^2(x)+tan^4(x))^2dx ? How do I evaluate the indefinite integral intx*sin(x)*tan(x)dx ? See all questions in Integrals of Trigonometric Functions Impact of this question 1463 views around the world You can reuse this answer Creative Commons License