What is int 289cos^4(17x)dx?

1 Answer
Jul 15, 2016

(17/32)(204 x + 8 sin 34 x-+sin 68 x) + C

Explanation:

Use cos^2 a = (1 + cos 2a )/2

289 int cos^4 (17 x) d x

= 289int ((1 + cos 34 x)/2)^2 d x

=(289/4)int ( 1 + 2 cos 34 x + co^2 34 x ) d x

= 289/4)int (1 + 2 cos 34 x + (1 + cos 68x)/2) d x

=(289/4)(x + (2/34) sin 34 x +x/2+(1/136)sin 68x) + C

=(17/32)(204 x + 8 sin 34 x+sin 17 x) + C