What is $int sinx cosx$ ?

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Answer 1 · 2016-01-27T16:22:21

$\intcos(x)sin(x)dx=\frac{-1}{4}cos(2x)+c$

Given equation is $\intcos(x)sin(x)dx$

I believe you're familiar with the trigonometric identity $sin(2\theta)=2sin(\theta)cos(\theta)$
So, the equation becomes $\frac{1}{2}\intsin(2x)dx$

I'm sure you know what to do from here to get the equation I got there above.

Answer 2 · 2016-01-31T14:51:31

There are 3 equivalent results:
$(sin^2x)/2+C$
$-(cos^2x)/2+C$
$-(cos(2x))/4+C$

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What is int sinx cosx int sinx cosx ?