What is $\int x sin (x - \frac{π}{2})$ $int xsin(x-pi/2)$ ?

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Answer 1 · 2018-03-27T12:46:02

The answer is $= - x sin x - cos x + C$ $=-xsinx-cosx+C$

The integral is

$I = \int x sin (x - \frac{π}{2}) d x = - \int x cos x d x$ $I=intxsin(x-pi/2)dx=-intxcosxdx$

$intuv'=uv-intu'v$

$u=x$ , $=>$ , $u'=1$

$v'=cosx$ , $=>$ , $v=sinx$

Therefore,

$I=-xsinx+intsinxdx$

$=-xsinx-cosx+C$

What is int xsin(x-pi/2) ∫xsin(x−π2)int xsin(x-pi/2) ?