What is the antiderivative of cos^2 x? Calculus Introduction to Integration Integrals of Trigonometric Functions 1 Answer VNVDVI May 13, 2018 x/2+1/4sin2x+C Explanation: Recall the cosine power reduction formula, cos^2x=1/2(1+cos2x) Then, intcos^2xdx=1/2int(1+cos2xdx)=1/2(intdx+intcos2xdx) =1/2(x+1/2sin2x+C)=x/2+1/4sin2x+C Answer link Related questions How do I evaluate the indefinite integral intsin^3(x)*cos^2(x)dx ? How do I evaluate the indefinite integral intsin^6(x)*cos^3(x)dx ? How do I evaluate the indefinite integral intcos^5(x)dx ? How do I evaluate the indefinite integral intsin^2(2t)dt ? How do I evaluate the indefinite integral int(1+cos(x))^2dx ? How do I evaluate the indefinite integral intsec^2(x)*tan(x)dx ? How do I evaluate the indefinite integral intcot^5(x)*sin^4(x)dx ? How do I evaluate the indefinite integral inttan^2(x)dx ? How do I evaluate the indefinite integral int(tan^2(x)+tan^4(x))^2dx ? How do I evaluate the indefinite integral intx*sin(x)*tan(x)dx ? See all questions in Integrals of Trigonometric Functions Impact of this question 16107 views around the world You can reuse this answer Creative Commons License