What is the antiderivative of cos(x)sin(sin(x))dxcos(x)sin(sin(x))dx?
1 Answer
Apr 19, 2016
Explanation:
We will want to make use of the following integral:
intsin(u)du=-cos(u)+C∫sin(u)du=−cos(u)+C
Thus, we want to set the interior of the
So, we want to set
Thus, we have
intcos(x)sin(sin(x))dx=intsin(sin(x))*cos(x)dx∫cos(x)sin(sin(x))dx=∫sin(sin(x))⋅cos(x)dx
=intsin(u)du=-cos(u)+C=-cos(sin(x))+C=∫sin(u)du=−cos(u)+C=−cos(sin(x))+C