What is the arclength of f(t) = (tlnt,t/lnt) on t in [1,e]?

1 Answer
Feb 10, 2017

The arc length is infinite.

Explanation:

Notice that lim_(trarr1^+)t/lnt=oo, since ln(1)=0. This means that the arc length is infinite, as the function is asymptotic at t=1.

We can also note that if we attempt to apply the arc length formula L=int_a^bsqrt((dx/dt)^2+(dy/dt)^2)dt, the integral diverges.

Attached is a plot of the parametric graph for tin(1,e]:

Desmos