What is the area of a triangle with sides 10, 10 and 16?

1 Answer
Alan P.
Jun 1, 2015

The height of a triangle with sides 10, 10, and 16, if we use 16 as the base is 6 (Pythagorean Theorem and diagram below).

Therefore the area of the triangle is
A=1/2bh = 1/2*16*6 = 48A=12bh=12⋅16⋅6=48
enter image source here

Alternately you could use Heron's formula
A=sqrt(s(s-a)(s-b)(s-c))A=√s(s−a)(s−b)(s−c) for a triangle with sides a, b, and ca,b,andc and a semi-perimeter of ss.

In this case s=18s=18
and
the area =sqrt(18(8)(8)(2)) = sqrt(36*8^2) = 6*8 = 48=√18(8)(8)(2)=√36⋅82=6⋅8=48

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