What is the area of a triangle with sides 10, 10 and 16?

1 Answer
Jun 1, 2015

The height of a triangle with sides 10, 10, and 16, if we use 16 as the base is 6 (Pythagorean Theorem and diagram below).

Therefore the area of the triangle is
A=1/2bh = 1/2*16*6 = 48
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Alternately you could use Heron's formula
A=sqrt(s(s-a)(s-b)(s-c)) for a triangle with sides a, b, and c and a semi-perimeter of s.

In this case s=18
and
the area =sqrt(18(8)(8)(2)) = sqrt(36*8^2) = 6*8 = 48