What is the area of a triangle with sides of length 1, 2, and 2?

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Answer 1 · 2016-01-25T08:52:23

$Area=sqrt15/4$ square units

Use the Heron's formula

$Area=sqrt(s*(s-a)(s-b)(s-c)$

Let $a=2, b=2, c=1$

compute $s$

$s=1/2(a+b+c)=1/2*(2+2+1)=5/2$

Now, compute the Area

$Area=sqrt(s*(s-a)(s-b)(s-c)$

$Area=sqrt(5/2*(5/2-2)(5/2-2)(5/2-1)$

$Area=sqrt(5/2*(1/2)(1/2)(3/2))=sqrt(15/16)=sqrt15/4$